X^2(x+1)=4(2x+3)

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Solution for X^2(x+1)=4(2x+3) equation: 



X^2(X+1)=4(2X+3)

We move all terms to the left:

X^2(X+1)-(4(2X+3))=0



We calculate terms in parentheses: -(4(2X+3)), so:

4(2X+3)

We multiply parentheses

8X+12

Back to the equation:

-(8X+12)



We get rid of parentheses

X^2(X+1)-8X-12=0

We move all terms containing X to the left, all other terms to the right

X^2(X+1)-8X=12

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